Answer:
Two real solutions
Step-by-step explanation:
Given is a graph of a parabola with quadratic equation.
We know that [tex]y = ax^2+bx+c[/tex]
has solution as x intercepts of the graph.
Using the above we find that the given graph has solution at the x intercepts.
X intercepts are 0 and -4
Hence the solutions are two real and they are x=0 and x =-4
Verify:
The graph is the transformation of [tex]y = x^2[/tex] by verical shift of 4 units down and horizontal shift of 2 units left
So equation would be
[tex]y = (x+2)^2-4[/tex]
Simplify to get
[tex]y = x^2+4x = x(x+4)[/tex]
Hence solutoins are x=0 or x = -4
