A merchant has coffee worth $60 a pound that she wishes to mix with 50 pounds of coffee worth $90 a pound to get a mixture that is worth $70 a pound. how many pounds (lb) of the $60 coffee should be used?

Respuesta :

Answer:

Step-by-step explanation:

Alright, lets gets started.

Suppose she mixes x pounds of coffee of $ 60 a pound.

So, the cost of that coffee = [tex]60x[/tex]

Merchant has 50 pounds of coffee worth $ 90 a pound, hence the cost of this second coffee = [tex]90*50=4500[/tex]

The mixture she get, is worth $ 70 and the weight of this mixture will be [tex](x+50)[/tex]

So, the cost of mixture will be = [tex]70*(x+50)[/tex]

Addition of both coffees will be equal to the mixture, so

[tex]60x + 4500 = 70(x+50)[/tex]

[tex]60x + 4500 = 70x + 3500[/tex]

Subtracting 60 x in both sides

[tex]4500=10x + 3500[/tex]

Subtracting 3500 in both sides

[tex]10x = 1000[/tex]

Dividing 10 in both sides

x = 100 pounds

It means she needs to add 100 pounds of that coffee.  :  Answer

Hope it will help :)