Respuesta :
As the atmospheric pressure is, P = dgh
Here d is the density of the mercury,
g is gravitation = 9.8 m/s²
h is height of the column, P = 751 torr = (751 torr × 1 atm / 760 torr) (101325 Pa) (1 N/m² / 1 Pa) = 100125 N/m²
Where, 1 N = 1 Kg / ms²
Thus, P = 100125 Kg / m³. s²
Therefore, height of the mercury column, when the atmospheric pressure is 751 torr,
h = P / gd
= (100125 kg / m³. s²) / (9.8 m/s²) (13.6 × 10³ kg / m³) = 0.751 m
As, d₁h₁ = d₂h₂
Here, d₁ is the density of the non-volatile liquid = 1.20 g/ml
d₂ is the density of the mercury = 13.6 g/ml
h₂ = 0.751 m
Thus, putting the values we get,
h₁ = d₂h₂ /d₁ = 13.6 g/ml × 0.751 m / 1.20 g/ml
= 8.5 m
8.5 m is the height of a barometer column based on 1-iodododecane.
How we calculate the height?
For the given question we will use the below formula:
P = dgh, where
g = gravitational force = 9.8 m/s²
First we calculate the height of the barometer column for the mercury:
Density of mercury = 13.6g/ml (given)
Given pressure = 751 torr = 100125 N/m² or 100125 Kg / m³.s²
Height of barometer for mercury = 100125 / (13.6×9.8) = 0.751 m
Now we calculate the height of barometer by using the below formula:
d₁h₁ = d₂h₂, where
d₁ = density of 1-iodododecane = 1.20g/mol (given)
h₁ = to find?
d₂, h₂ = density & height with respect to mercury
On putting all values in the above equation we get,
h₁ = 13.6×0.751 / 1.20 = 8.5m
Hence, 8.5m is the height of barometer.
To know more about height of barometer, visit the below link:
https://brainly.com/question/16021487
