Respuesta :

0  Pretend that is theta XD


cot 0 = [tex]\frac{1}{tan0}[/tex]


Find tan 0.

tan 0 = [tex]\frac{y}{x}[/tex]

tan 0 = [tex]\frac{-3\sqrt{5}}{-6}[/tex]

tan 0 = [tex]\frac{\sqrt{5}}{2}[/tex]


cot 0 = [tex]\frac{1}{tan0}[/tex]

cot 0 = [tex]\frac{1}{\frac{\sqrt{5} }{2} }[/tex]    

Multiply 2/√5 to the numerator and the denominator (or multiply the reciprocal of the denominator to the top and bottom of the fraction)

cot 0 = [tex]\frac{1}{\frac{\sqrt{5}}{2} } (\frac{\frac{2}{\sqrt{5}} }{\frac{2}{\sqrt{5}}} )[/tex]

cot 0 = [tex]\frac{2}{\sqrt{5}}[/tex]  

Multiply √5 to the numerator and the denominator

cot 0 = [tex]\frac{2}{\sqrt{5}} (\frac{\sqrt{5} }{\sqrt{5} })[/tex]

cot 0 = [tex]\frac{2\sqrt{5}}{5}[/tex]