Answer:
Hence no of cars (C) is 14, and no of bikes, M is 7.
Step-by-step explanation:
Let the no of cars be C and number of motorcycles be M.
First statement mentions that no of cars (c) is twice no of motorbikes, hence
C=2M
Second statement says, when no of cars is increased by 1, and motorcycles is reduced by 2, the calculations change as-
C+1 = 3(M-2)
On solving the two, we have
C=2M
C+1=3(M-2)
Solving eq 2
C+1=3M-6 (Subtracting 1 from both sides)
C=3M-7
Putting eq 1 & 2 together-
3M-7=2M (sub 2m from both sides)
M-7=0
M=7
Now M is 7. Put it in eq 1
C=2M
C=2(7)
C=14
Hence no of cars (C) is 14, and no of bikes, M is 7.