Jetc34
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during batting practice, the ballplayer swings his bat with a velocity of 14 m/s. If the bat is 0.65m long, what is the centripetal acceleration at the end of the bat? (Ignore the length of the ballplayer's arm)

Respuesta :

Your answer will be 301.5386

According to my research on centripetal acceleration:

Centripetal Acceleration:  Acceleration is in the direction of the change in velocity, which points directly towards the center of rotation, the center of the circular path.


Formula for a centripetal acceleration (ac):

[tex]a_{c} = \frac{v^{2}} {r}[/tex]

Here v = velocity and r = radius.


Unit for centripetal acceleration:

Unit for v = m/s

unit of r = m

ac = (m/s)^2 / m

ac = (m^2 / s^2) / m

ac = m/s^2


Given: v = 14 m/s and d = 0.65 m

so the radius (r) = diameter (d) / 2

0.65 / 2 = r = 0.325 m


Now calculating ac:

(ac = centripetal acceleration)

ac = v^2 / r

ac = (14) ^2 / 0.325

ac = 196 / 0.325

ac = 603.08 m/s^2


// I am not sure, if I am right, but hope it helps