From points A and B, the distance between which is 1020 mi, two trains left simultaneously towards each other. The speed of one train was 10 mph greater than the speed of the other one. In 5 hours the trains had not met yet and were 170 mi apart. Find the speed of the trains.

PLz just give me the answer!!!

Respuesta :

From points A and B, the distance between which is 1020 mi

The speed of one train was 10 mph greater than the speed of the other one

Let the Speed of first train is x

Speed of second train is x+ 10

Time = 5 hours

Distance = speed * time

Distance traveled by first train = x * 5= 5x

Distance traveled by second  train = (x+10) * 5= 5x + 50

the trains had not met yet and were 170 mi apart.

the distance between A  and B is 1020 mi, Distance traveled by two trains = 1020 - 170 = 850 miles

Distance traveled by first train + second train = 850

5x + 5x + 50 = 850

10x + 50 = 850

Subtract both sides by 50

10x = 800

x= 80

Speed of first train is 80 miles per hour

Speed of second train is 90 miles per hour


The speed of the trains are 80 mph and 90 mph

Speed is the ratio of distance travelled to time taken. It is given by:

Speed = distance/time

Let the distance travelled by the train moving at 10 mph greater after 5 hours be d₁ while he distance travelled by the train moving at x mph after 5 hours be d₂, hence:

x + 10 = d₁/5

d₁ = 5x + 50

x = d₂/5

d₂ = 5x

d₁ + d₂ = 1020 - 170

d₁ + d₂ =850

5x + 50 + 5x = 850

10x = 800

x = 80 mph

x + 10 = 90 mph

Hence the speed of the trains are 80 mph and 90 mph

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