Respuesta :
Let's let
x = the number of chef salads, x>=0
y = the number of Caesar salads, y>=0
The constrains are:
40 <= x <= 60
35 <= y <= 50
x + y <= 100
The objective function here is F(x, y) = 0.75x + 1.20y
The corner points are (40, 35), (60, 35), (60, 40), (50, 50) and (40, 50).
F (40, 35) = 0.75*40 + 1.20*35 = $72
F (60, 35) = 0.70*60 + 1.20*35 = $84
F (60, 40) = 0.75*60 + 1.20*40 = $93
F (50, 50) = 0.75*50 + 1.20*50 = $97.50
F (40, 50) = 0.75*40 + 1.20*50 = $90
Thus, we conclude to maximize the profit 50 Chef and 50 Caesar salads should be prepared.
50 Caesar salads and 50 chef's salads should be prepared in order to maximize profit.
Since a lunch stand makes $ 0.75 profit on each chef's salad and $ 1.20 profit on each Caesar salad, and on a typical weekday, it sells between 40 and 60 chef's salads and between 35 and 50 Caesar salads, and the total number sold has never exceeded 100 salads, to determine how many of each type should be prepared in order to maximize profit, the following calculation must be performed:
The maximum number of salads to be produced must be determined, combining both options: 50 Caesar salads and 50 chef's salads.
- 50 x 1.2 + 50 x 0.75 = X
- 60 + 37.5 = X
- 97.5 = X
Therefore, 50 Caesar salads and 50 chef's salads should be prepared in order to maximize profit.
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