Respuesta :
Answer: First option: 800 feet
Solution:
Height: h=400 sqrt(3)
Distance between the zoo and the point in the ground below the helicopter: d1=?
Distance between the library and the point in the ground below the helicopter: d2=?
Distance between the zoo and the library: d=?
d=d2-d1
tan 60°= h/d1
sqrt(3)=400 sqrt(3) / d1
Solving for d1:
sqrt(3) d1 = 400 sqrt(3)
d1= 400 sqrt(3) / sqrt(3)
d1=400
tan 30°= h/d2
sqrt(3) / 3=400 sqrt(3) / d2
Solving for d2: Cross multiplication:
sqrt(3) d2 = 3 [ 400 sqrt(3) ]
sqrt(3) d2 = 1,200 sqrt(3)
d2= 1,200 sqrt(3) / sqrt(3)
d2=1,200
d=d2-d1
d=1,200 feet - 400 feet
d=800 feet
Answer:
800 ft
Step-by-step explanation:
We know that the helicopter is flying [tex]400\sqrt{3}[/tex] feet above the ground.
A zoo and the library are on the same side of the helicopter, each making an angle of 60° and 30° respectively on the line joining the helicopter with the ground.
So we know it makes a right angled triangle with two different angles at the same side and a perpendicular of [tex]400\sqrt{3}[/tex].
Assuming x to be the distance from helicopter to the library on the ground and y to the distance from helicopter to the zoo on the ground:
[tex]tan 30[/tex]° [tex]=\frac{400\sqrt{3} }{x}[/tex]
[tex]x = 1200 ft[/tex]
[tex]tan 60[/tex]° [tex]= \frac{400\sqrt{3} }{y}[/tex]
[tex]y= 400 ft[/tex]
Distance between the zoo and the library = x - y = 1200 - 400 = 800 ft