Answer: It takes 0.000092742 seconds the proton to go arond the 17 mile circumference of the collider.
Solution:
Velocity: v=295,000,000 meters / second
Time: t=?
Distance: d=17 miles (1609.344 meters / 1 mile)→d=27,358.848 meters
v=d/t
Replacing the given values:
295,000,000 meters / second = 27,358.848 meters / t
Solving for t:
(295,000,000 meters / second) t = 27,358.848 meters
t=(27,358.848 meters) / (295,000,000 meters / second)
t=0.000092742 seconds
Answer:
9.27 x 10^-5 seconds
Step-by-step explanation:
We are given the speed of the proton at which it travels i.e. 295,000,000 meters per second.
And we also know the total circumference of the collider = 17 mile.
So to find the time taken the proton to travel around the circumference of the collider, we first need to make the units same.
1 mile = 1609.34 meters
17 mile = 1609.34 * 17 = 27358.78
Time taken by the proton = distance / speed
= 27358.78 / 295000000
= 9.27 x 10^-5
Therefore, it takes 9.27 x 10^-5 or 0.0000927 seconds for the proton to go around 17 mile circumference of the collider.
