3 and 4
solving each of the inequalities
1. distribute left side
36 + 6x > 54 ( subtract 36 from both sides )
6x > 18 ( divide both sides by 6 )
x > 3
2.
2x + 6x > 15 + 3x
8x > 15 + 3x ( subtract 3x from both sides )
5x > 15 ( divide both sides by 5 )
x > 3
3. (add 9 to both sides )
7 < [tex]\frac{x}{3}[/tex] ( multiply both sides by 3 )
21 < x or x > 21
4.
subtract 5 from both sides
[tex]\frac{x}{4}[/tex] > - 3 ( multiply both sides by 4 )
x > - 12
3 and 4 have solutions that are not x > 3