We are given equation [tex]y = -3x^2[/tex].
We need to check the given table.
We have x=-2,-1,0,1,2 in the given table.
Plugging x=-2,-1,0,1,2 in the given equation
For x=-2
y = -3 (-2)^2 = -3(4) = -12
For x =-1
y = -3 (-1)^2 = -3(1) = -3
For x =-0
y = -3 (0)^2 = -3(0) = 0
For x =1
y = -3 (1)^2 = -3(1) = -3
For x =2
y = -3 (2)^2 = -3(4) = -12.
Therefore, correct table is
x y (x,y)
_____________
-2 -12 (-2,-12)
-1 -3 (-1,-3)
0 0 (0,0)
1 -3 (1,-3)
2 -12 (2,-12).
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