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Answer
Proof of (a)
Disagree with the ΔABD = ΔCBD by the SAS congruence postulate .
SAS congurence property
In this congurence property two sides and one angle of the two triangles are equal .
(1) BD = BD ( Common sides of the ΔABD and ΔCBD )
(2) AB =BC (B is the midpoint of the AC i.e it bisect AC in the two equal parts.)
but equal angles are not given
therefore disagree with the ΔABD = ΔCBD by the SAS congurence postulate .
Proof of (b)
SSS congurence property
In this congurence property three sides of the two triangles are equal .
In the ΔABD and ΔCBD .
(1) BD = BD ( Common sides of the ΔABD and ΔCBD )
(2) AB =BC (B is the midpoint of the AC i.e it bisect AC in the two equal parts.)
(3) AD=CD (Given )
ΔABD = ΔCBD by the SSS congurence theorem
Hence proved
A) Jeremy's statement that ∠ABD ≅ ∠CBD by the SAS congruence postulate; is not true and I will disagree with it because no included angle is given.
B) The postulate that can be used to prove that ∠ABD ≅ ∠CBD if AD = CD is; SSS Congruence postulate.
A) We are given that;
Point B is the midpoint of AC. Thus;
AB = BC
Also, by reflexive property of congruence,
BD = BD
Now, since BD bisects AC into 2 equal parts, but we are not told if the bisector is perpendicular and as such we can't say for sure that ∠ABD = ∠CBD.
Therefore, we have 2 corresponding sides but no angle has been given to be congruent and as such we will disagree with the SAS Congruence postulate used.
B) We are told that AB = CD
From part A above, we established that AB = BC and BD = BD
Since the three corresponding sides of ΔABD and ΔCBD are congruent to each other, then we can say that ΔABD and ΔCBD are congruent by the SSS Congruence postulate.
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