The answer is: D) 115
The explanation is shown below:
1. You have that the frequency with which a cricket chirps varies directly with the temperature, which you can express it as following:
[tex]y=kx[/tex]
Where [tex]y[/tex] is the frequency with which a cricket chirps, [tex]x[/tex] is the temperature and [tex]k[/tex] is the constant of proportionality.
2. If the cricket chirps 100 times per minute in 80° weather, you can calculate [tex]k[/tex] as below:
[tex]k=\frac{100}{80}=1.25[/tex]
3. Therefore, the frequency in 92° weather is:
[tex]y=1.25x\\y=(1.25)(92)\\y=115[/tex]
