Shelly ran 2 1/4 miles. Lynne ran 3 1/8 miles. Who ran farther and by how much? A. Lynne by 3/4 miles B. Lynne by 7/8 miles C. Shelly by 3/4 miles D. Shelly by 7/8 miles

Respuesta :

Answer:

Lynne ran farther and by 7/8 miles.

Step-by-step explanation:

We know that,

the number of miles Shelly ran = [tex]2\frac{1}{4}[/tex]; and

the number of miles Lynne ran = [tex]3\frac{1}{8}[/tex]

To find who ran farther and by how much, we need to find the difference between the number of miles which Shelly and Lynne had run.

Converting the mixed fractions to improper fractions:

Shelly = [tex]\frac{9}{4}[/tex]

Lynne = [tex]\frac{25}{8}[/tex]

Taking the bigger fraction and subtracting the smaller one from it to get:

[tex]\frac{25}{8} -\frac{9}{4}[/tex]

[tex]=\frac{25-18}{8}[/tex]

[tex]=\frac{7}{8}[/tex]

Therefore, Lynne ran farther and by 7/8 miles.