Which of the following correctly simplifies the expression 3 to the power of 2 multiplied by 5 to the power of 0 whole over 4, the whole squared.? 3 to the power of 2 multiplied by 1 whole over 4, the whole squared. = 3 to the power of 1 multiplied by 1 squared over 4 squared. = 1 over 6. 3 to the power of 2 multiplied by 0 whole over 4, the whole squared. = 3 to the power of 4 multiplied by 0 over 4 squared. = 0 3 to the power of 2 multiplied by 0 whole over 4, the whole squared. = 3 to the power of 1 multiplied by 0 over 4 squared. = 0 3 to the power of 2 multiplied by 1 whole over 4, the whole squared. = 3 to the power of 4 multiplied by 1 squared over 4 squared. = 81 over 16.

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Answer:

It is D i just took the test

Step-by-step explanation:

it = 5 1/6 it equals 81/16

Option D: [tex]\dfrac{3^4 \times 1^2}{4^2} = \dfrac{81}{16}[/tex]  is the correct simplification of the given expression.

Given the expression:

  • [tex](\dfrac{3^2 \times 5^0}{4})^2[/tex]

Simplification of given expression:

For simplifying the given expression, open the bracket and the power of 2 will multiply both numerator and denominator to get multiplied by themselves twice.

[tex]\begin{aligned} (\dfrac{3^2 \times 5^0}{4})^2 &= (\dfrac{3^2 \times 1}{4})^2\\\\&= \dfrac{3^{2 \times 2} \times 1^{1 \times 2}}{4^2}\\\\&= \dfrac{3^4 \times 1^2}{4^2}\\\\&= \dfrac{81}{16}\\\\\end{aligned}[/tex]

Hence, option D: [tex]\dfrac{3^4 \times 1^2}{4^2} = \dfrac{81}{16}[/tex]  is the correct simplification of the given expression.

Learn more about simplification of equations here:

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