Respuesta :
at the highest point of the trajectory of the ball only horizontal component of the velocity will remain as there is no acceleration in horizontal direction.
But due to gravity in vertical direction the vertical component of the velocity will become zero at the highest point
so here we can say that at highest point we will have
[tex]v_x = 22 cos40 = 16.85 m/s[/tex]
[tex]v_y = 0[/tex]
now for the kinetic energy we can say
[tex]K = \frac{1}{2} mv^2[/tex]
here we know that
[tex]m = 0.150 kg[/tex]
[tex]v = v_x = 16.85 m/s[/tex]
now the kinetic energy will be given as
[tex]K = \frac{1}{2}*0.150*16.85^2[/tex]
[tex]K = 21.3 J[/tex]
so kinetic energy will be 21.3 J
The value of kinetic energy of the baseball thrown by the school's team at the highest point of its trajectory is 21.3 J.
What is kinetic energy?
Kinetic energy is a type of energy, which a body is posses due to its motion. The kinetic energy of a body can be found with the following formula,
[tex]KE=\dfrac{1}{2}mv^2[/tex]
Here, (m) is the mass of the body, and (v) is the speed of the body.
The speed of the baseball is 22 m/s. The initial angle of the ball is 40.0 degrees. Thus the horizontal component of the velocity at the highest point can be given as,
[tex]v_h=22\cos(40^o)\\v_h=16.85\rm m/s[/tex]
The vertical component of the velocity at the highest point is zero, Thus, we have only a horizontal component of velocity acting on the body at the highest point.
As, the mass of the baseball is 0.150 kg. Thus, put the values in the above formula as,
[tex]KE=\dfrac{1}{2}(0.15)(16.85)^2\\KE=21.3\rm J[/tex]
Hence, the value of kinetic energy of the baseball thrown by the school's team at the highest point of its trajectory is 21.3 J.
Learn more about the kinetic energy here;
https://brainly.com/question/25959744
