Solve x + 3y + z = 1
2x – y – z = 6
5x + y + z = 1

(1, 6, 1)

(1, 2, -6)

(2, 1, -4)

(-1, -2, 6)

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lisboa lisboa · Answer 1 · 2018-10-04T02:06:23+02:00

Answer is (1, 2, -6)

x + 3y + z = 1 -------> first equation

2x – y – z = 6 -------> second equation

5x + y + z = 1 -------> third equation

Add second and third equation

2x – y – z = 6 -------> second equation

5x + y + z = 1 -------> third equation

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7x = 7 (divide by 7 on both sides)

So x= 1

Now we add first and second equations

x + 3y + z = 1 -------> first equation

2x – y – z = 6 -------> second equation

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3x +2y = 7

We already got x=1, replace it in the above equation

3(1) + 2y = 7

3 + 2y = 7 (subtract 3)

2y = 4 (divide both sides by 2)

So y =2

Now plug in the values in first equation

x + 3y + z = 1 -------> first equation

1 + 3(2) + z = 1

7 + z = 1 (subtract 7 from both sides)

z = -6

Answer is (1, 2, -6)