Solution :
Given equations, [tex]x-y=3\\2x+2y=2[/tex]
Applying Substitution method to solve the equation.
Solve the first equation [tex]x-y=3[/tex] for x,
[tex]x-y=3\:\Rightarrow x=3+y[/tex]
Substitute the value of x in second equation,
[tex]2x+2y=2\\\\\Rightarrow 2(3+y)+2y=2\\\\\Rightarrow 6+2y+2y=2\\\\\Rightarrow6+4y=2\\\\\Rightarrow4y=2-6\\\\\Rightarrow4y=-4\\\\\Rightarrow y=\frac{-4}{4} =-1\\\\\Rigtharrow y=-1[/tex]
To calculate the value of x substitute the value of y in first equation
[tex]x-y=3\\\\\Rightarrow x-(-1)=3\\\\\Rightarrow x=3-1=2\\\\\Rightarrow x=2[/tex]
Hence, the solution of the equations [tex]x-y=3\\2x+2y=2[/tex] is (2,-1).
