A migrating robin flies due north with a speed of 12 m/s relative to the air. The air moves due east with a speed of 6.7 m/s relative to the ground. Part A What is the robin's speed relative to the ground?

Respuesta :

Here it is given that speed of migrating Robin is 12 m/s relative to air

so we can say that

[tex]\vec v_{ra} = 12 m/s[/tex] North

so it will be

Let North direction is along Y axis and East direction is along X axis

[tex]\vec v_{ra} = 12\hat j[/tex]

also it is given that speed of air is 6.7 m/s relative to ground

[tex]\vec v_a = 6.7 \hat i[/tex]

now as we know by the concept of relative motion

[tex]\vec v_{ab} = \vec v_a - \vec v_b[/tex]

[tex]\vec v_{ra} = \vec v_r  - \vec v_a[/tex]

now by rearranging the terms

[tex]\vec v_r = \vec v_{ra} + \vec v_a[/tex]

[tex]\vec v_r = 12 \hat j + 6.7 \hat i[/tex]

now we need to find the speed of Robin which means we need to find the magnitude of its velocity which we found above

So here we will say

[tex]v_r = \sqrt{12^2 + 6.7^2}[/tex]

[tex]v_r = 13.7 m/s[/tex]

so the net speed of Robin with respect to ground will be 13.7 m/s