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What is the average rate of change of the function f(x)=120(0.1)^x from x = 0 to x = 2? Enter your answer, as a decimal, in the box. Do not round your answer.

Respuesta :

Answer:

[tex]Average\:Rate\:Change=-59.4[/tex]

Step-by-step explanation:

The given function is [tex]f(x)=120(0.1)^x[/tex].


We want to find the average rate of change of this function from [tex]x=0[/tex] to [tex]x=2[/tex].


This is given by:

[tex]Average\:Rate\:Change=\frac{f(2)-f(0)}{2-0}[/tex]


This implies that;


[tex]Average\:Rate\:Change=\frac{120(0.1)^2-120(0.1)^0}{2-0}[/tex]


[tex]Average\:Rate\:Change=\frac{120(0.1)^2-120}{2}[/tex]


[tex]Average\:Rate\:Change=\frac{120((0.1)^2-1)}{2}[/tex]


[tex]Average\:Rate\:Change=\frac{60(0.01-1)}{1}[/tex]


[tex]Average\:Rate\:Change=60(-0.99)[/tex]


[tex]Average\:Rate\:Change=-59.4[/tex]

Answer:

Give Me Brainliest, PS -59.4 is the answer

Step-by-step explanation:

Just took the test