For this case we have the following equation:
[tex]\frac{2}{3}x-\frac{1}{3}= 2 (x + 2)\\[/tex]
If we multiply both sides of the equation by 3 we get:
[tex]2x-1 = 6 (x + 2)[/tex] ---> Multiplication Property of Equality
Applying the distributive property we have:
[tex]2x-1 = 6x + 12[/tex] ---> Distributive Property
Adding 1 on both sides of equality we have:
[tex]2x-1 + 1 = 6x + 12 + 1\\[/tex]
[tex]2x = 6x + 13[/tex] ---> Addition Property of Equality
Subtracting [tex]6x[/tex] on both sides we have:
[tex]-6x + 2x = 6x-6x + 13\\[/tex]
[tex]-4x = 13[/tex] ---> Subtraction Property of Equality
Finally, dividing by -4 on both sides we have:
[tex]\frac{-4x}{-4}= \frac{13}{-4}\\[/tex]
[tex]x = -\frac{13}{4}[/tex]---> Division Property of Equality
