Respuesta :
Kiran is correct. (I agree with Kiran.)
_____
Suppose the length and width are L and W. The Pythagorean theorem says the diagonal distance is ...
... d = √(L² +W²)
If the dimensions are doubled, the the diagonal distance becomes ...
... D = √((2L)² +(2W)²) = √(4(L² +W²)) = 2√(L² +W²)
... D = 2d
Answer:
Kiran's statement is correct.
Step-by-step explanation:
Kiran says that if the field were twice as long and twice as wide, then it would be twice the distance to the far corner.
Let the original length be = l
Let the original width be = w
Let the original diagonal be = d1
As per Pythagoras theorem,
[tex]d1^{2} =l^{2} +w^{2}[/tex]
When the dimensions are twice the original;
Length = 2l
Width = 2w
Diagonal = d2
We get the formula :
[tex]d2^{2} =2l^{2} +2w^{2}[/tex]
[tex]d2^{2} =2(l^{2} +w^{2})[/tex]
Or [tex]d2^{2} =2d1^{2}[/tex]
So, we can say that Kiran is correct.