Given: AO = OD
OB = OC
m∠1=74˚, m∠2=36˚
Find: m∠ACD

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Jennnyyy Jennnyyy · Answer 1 · 2018-10-02T23:50:07+02:00

First of all m<1 + m<2 = m<ACD

Soo we just need to add them.

74 + 36 = 110

So m<ACD = 110 degrees.

GOOD LUCK! :)

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erinna erinna · Answer 2 · 2019-10-23T11:21:11+02:00

Answer:

[tex]m\angle ACD=110^{\circ}[/tex]

Step-by-step explanation:

Given information: AO = OD, OB = OC, m∠1=74˚, m∠2=36˚.

In triangle OAB and ODC,

[tex]AO=OD[/tex] (Given)

[tex]m\angle AOB=m\angle DOC[/tex] (Vertical angles)

[tex]OB=OC[/tex] (Given)

By SAS postulate,

[tex]\triangle OAB\cong \triangle ODC[/tex]

[tex]\angle OBA\cong \triangle OCD[/tex] (CPCTC)

[tex]m\angle OBA=m\triangle OCD[/tex]

[tex]74^{\circ}=m\triangle OCD[/tex]

From the given figure it is clear that

[tex]\angle ACD=\angle ACO+\angle OCD[/tex]

[tex]\angle ACD=36^{\circ}+74^{\circ}[/tex]

[tex]\angle ACD=110^{\circ}[/tex]

Therefore, the measure of angle ACD is 110°.