Respuesta :

(x - 12 )(x + 4 )

consider the factors of - 48 which sum to - 8. These are - 12 and + 4

x² - 8x - 48 = (x - 12)(x + 4) ( in factored form )


Answer:

[tex](x+4)(x-12)[/tex]

Step-by-step explanation:

[tex]x^2-8x-48[/tex]

Factor the given expression

Product is -48 and sum is -8

-12 times 4 is -48

-12 plus 4 is -8

So two factors that gives us product -48 ans um -8 is -12 and 4

LEts break -8x using the factors

[tex]x^2-8x-48[/tex]

[tex]x^2-12x+4x-48[/tex] Group the terms

[tex](x^2-12x)+(4x-48)[/tex], Take out GCf from each group

[tex]x(x-12)+4(x-12)[/tex]

Now factor out x-12

[tex](x+4)(x-12)[/tex]