Respuesta :
(x - 12 )(x + 4 )
consider the factors of - 48 which sum to - 8. These are - 12 and + 4
x² - 8x - 48 = (x - 12)(x + 4) ( in factored form )
Answer:
[tex](x+4)(x-12)[/tex]
Step-by-step explanation:
[tex]x^2-8x-48[/tex]
Factor the given expression
Product is -48 and sum is -8
-12 times 4 is -48
-12 plus 4 is -8
So two factors that gives us product -48 ans um -8 is -12 and 4
LEts break -8x using the factors
[tex]x^2-8x-48[/tex]
[tex]x^2-12x+4x-48[/tex] Group the terms
[tex](x^2-12x)+(4x-48)[/tex], Take out GCf from each group
[tex]x(x-12)+4(x-12)[/tex]
Now factor out x-12
[tex](x+4)(x-12)[/tex]