Given : f(x)=2x+1 and g(x)=x^2-1.
We need to find (f/g)(x).
Note: In the given options, we have 2x + 1 and x^2 - 7 parts.
So, let us take f(x)=2x+1 and g(x)=x^2-7.
[tex](f/g)(x) =\frac{f(x)}{g(x)}[/tex]
Plugging f and g functions in the formula.
[tex](\frac{f}{g})(x)=\frac{(2x+1)}{(x^2-7)}[/tex]
Also, it would be undefined for x = ± square root 7 becaue it would give 0 in the denomiantor.
Therefore, correct option is C. 2x + 1 / x^2 - 7, x ≠ ± square root 7.