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OmegaAzzy

2x + 5 ≤ x - 3

We can treat this like a usual algebraic equation.

Subtract x from both sides.

x + 5 ≤ -3

Subtract 5 from both sides.

x ≤ -8

Thus, x is less than or equal to the quantity -8.

We can test this by plugging in two values into the original inequality: a number greater than -8, and a number less than -8.

2x + 5 ≤ x - 3

We'll use 2 first.

2 * 2 + 5 ≤ 2 - 3

9 ≤ -1 × this is incorrect

Now  we'll use -10

2x + 5 ≤ x - 3

2 * -10 + 5 ≤ -10 - 3

-15 ≤ -13 √ this is correct



dubeyshailja64

Mathematics defines an algebraic equation as a statement in which a relationship between two expressions is established through an equals sign.

For the given question the equation will be:

            [tex]\rm 2x + 5 = x - 3[/tex]

On solving the above equation, x can be defined as -8.

Solution of Algebraic Equation.

Let the number be x.

According to the question:

Twice of x + 5 =  x - 3

This forms a quadratic equation:

             [tex]\rm 2x + 5 = x - 3[/tex]

The equation  [tex]\rm 2x + 5 = x + 3[/tex] can be solved as follows:

          [tex]\begin{aligned} \rm 2x + 5 &= x - 3\\\\ 2x - x &= -3 - 5\\\\x &= -8 \end[/tex]

Therefore the number is -8.

Learn more about quadratic equation here:

https://brainly.com/question/2263981

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