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Here's the question: You have an electrical circuit with various components, all of which are in series. The current (I) through the system is (5.772 - 5.323i) milliamperes (mA). The impedance (Z) in that same system is (3.342 + 4.176i) kilohms (kΩ). Please tell me the magnitude of the voltage in the circuit.

Respuesta :

Answer:Magnitude of voltage is 41.9963 volts


Step-by-step explanation:

Given that current I =5.772-5.323i mA

          and impedance, Z=3.342+4.176i kilo ohms

Then voltage in the circuit = IZ

                                            [tex]=(5.772-5.323i)X10^{-3}X(3.342+4.176i)X10^{3}[/tex]

                                      [tex]V=(5.772-5.323i)X(3.342+4.176i)[/tex]

                                      [tex]V=19.290024+24.103872i-17.789466i-23..5148848i^{2}[/tex]

                                     [tex]V=41.518892+6.314406i[/tex]

Magnitude of V = [tex]\sqrt{41.518892^{2} +6.314406^{2} }=\sqrt{1763.6901}=41.9963volts[/tex]


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