(a ) slope = - [tex]\frac{3}{4}[/tex] and y- intercept = 3
(b ) slope = - 2 and y- intercept = 1
The equation of a line in slope- intercept form is y = mx + c
where m is the slope and c the y- intercept
Rearrange each equation into this form
(a ) 3x + 4y - 12 = 0 ( subtract 3x - 12 from both sides )
4y = - 3x + 12 ( divide all terms by 4 )
y = - [tex]\frac{3}{4}[/tex] x + 3 ( in slope- intercept form )
with slope m = - [tex]\frac{3}{4}[/tex] and y - intercept c = 3
(b ) 2x + y = 1 ( subtract 2x from both sides )
y = - 2x + 1 ( in slope- intercept form )
with slope m = - 2 and y- intercept c = 1
