[tex]\underline{+\left\{\begin{array}{ccc}y=-x-1\\y=x+1\end{array}\right}\ \ \ \ |\text{add both sides}\\\\.\ \ \ \ \ 2y=0\ \ \ |:2\\.\ \ \ \ \ y=0\\\\\text{substitute the value of y to the second equation}\\\\0=x+1\ \ \ \ |-1\\x=-1\\\\Answer:\ A.\ (-1,\ 0)[/tex]
The solution of the system of equation is (-1, 0).
The system of equation is;
[tex]\rm y=-x-1\\\\y=x+1[/tex]
What is the solution to the system of equations?
The system of equation is;
[tex]\rm y=-x-1\\\\y=x+1[/tex]
Substitute the value y in equation 2 from equation 1.
[tex]\rm y = x+1 \\\\-x-1 = x+1\\\\-x-x = 1+1\\\\-2x = 2\\\\x = \dfrac{-2}{2}\\\\x = -1[/tex]
Substitute the value of x in equation 1
[tex]\rm y = -x-1\\\\y = -(-1)-1\\\\y = 1-1\\\\y= 0[/tex]
Hence, the solution of the system of equation is (-1, 0).
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