Problem N 10) Find the surface area
we know that
the surface area is equal to
SA=2*area of the base+perimeter of base*height
Find the area of the base B (area of a square)
[tex]B=42*42=1,764\ mm^{2}[/tex]
Find the perimeter of the base P (perimeter of a square)
[tex]P=4*42=168\ mm[/tex]
height=68 mm
substitute in the formula
[tex]SA=2*1,764+168*68=14,952\ mm^{2}[/tex]
therefore
the answer Problem N 10) is
the surface area is [tex]14,952\ mm^{2}[/tex]
Problem N 11) Find the volume
we know that
the volume is equal to
V=area of the base*height
find the area of the base A (area of a triangle)
[tex]A=\frac{1}{2}*6*8=24\ ft^{2}[/tex]
height =4 ft
substitute in the formula
[tex]V=24*4=96 \ ft^{3}[/tex]
therefore
the answer Problem N 11) is
the volume is equal to [tex]96 \ ft^{3}[/tex]
