Missing question:
1. How many quarts of antifreeze are in the resulting mixture?
2. What % of the resulting mixture is antifreeze?
1) V₁ = 14 qt; volume of solution.
ω₁ = 36% ÷ 100% = 0.36.
V₂ = 6 qt.
ω₂ = 12% ÷ 100% = 0.12.
V₃ = V₁ · ω₁ + V₂ · ω₂.
V₃ = 14 qt · 0.36 + 6 qt · 0.12.
V₃ = 5.76 qt; quarts of antifreeze in the resulting mixture.
2) ω₃ = V₃ / (V₁ + V₂) · 100%.
ω₃ = 5.76 qt / (14 qt + 6 qt) · 100%.
ω₃ = 28.8 %; % of the resulting mixture is antifreeze.
