Given the mass of aluminum sulfide[tex]Al_{2}S_{3}[/tex] = 21.0 g
Molar mass of [tex]Al_{2}S_{3}[/tex] = [tex]2 * Molar mass of Al + 3 *molar mass of S = 2(27g/mol)+3(32.g/mol)=150.g/mol[/tex]
Calculating the moles of [tex]Al_{2}S_{3}[/tex]:
[tex]21.0 g *\frac{1 mol}{150 g} = 0.14 mol Al_{2}S_{3}[/tex]
Each mole [tex]Al_{2}S_{3}[/tex] has 3 mol S.
Each mole S constitutes [tex]6.022*10^{23} atoms of S[/tex]
Calculating atoms of S in 0.14 mol [tex]Al_{2}S_{3}[/tex]:
[tex]0.14 mol Al_{2}S_{3} *\frac{3mol S}{1 mol Al_{2}S_{3} }*\frac{6.022*10^{23}atoms S }{1 mol S}[/tex]
= [tex]2.53 * 10^{23} atoms of S[/tex]
The study of chemicals and bonds is called chemistry. There are different types of elements and these are metals and nonmetals.
The correct answer is [tex]2.53*10^{23[/tex]
According to the question,
The mass of the [tex]AL_2S_3[/tex]. The moles [tex]AL_2S_3[/tex] are [tex]21.0*\frac{1}{150} = 0.14[/tex]
The molecules present in sulfur will be [tex]6.022*10^{23[/tex]. The molecules are as follows:-
[tex]0.14*\frac{3}{1}* \frac{6.022*10^{23}}{1\\}\\ =2.53*10^{23[/tex]
Hence, the correct answer is mentioned above.
For more information about the moles, refer to the link:-
https://brainly.com/question/9864045
