Respuesta :
a)
Consumption of power in one day = [tex]100 W \times 6.5 h = 650 Wh[/tex]
Consumption of power in one year = [tex]100 W \times 6.5 h\times 365 = 237250 Wh[/tex]
Since, [tex]1 Wh = 0.001 kWh[/tex]. So,
[tex]237250 Wh = 237.25 kWh[/tex]
Given that [tex]1 kWh[/tex] = [tex]$0.18[/tex]
So, for [tex]237.25 kWh[/tex]:
[tex]237.25 kWh\times[/tex] $ [tex]0.18/ kWh[/tex] = $[tex]42.705[/tex]
Hence, the annual cost is $[tex]42.705[/tex].
b)
Consumption of power in one day = [tex]25 W \times 6.5 h = 162.5 Wh[/tex]
Consumption of power in one year = [tex]25 W \times 6.5 h\times 365 = 59312.5 Wh[/tex]
Since, [tex]1 Wh = 0.001 kWh[/tex]. So,
[tex]59312.5 Wh = 59.3125 kWh[/tex]
Given that [tex]1 kWh[/tex] = [tex]$0.18[/tex]
So, for [tex]59.3125 kWh[/tex]:
[tex]59.3125 kWh\times[/tex] $ [tex]0.18/ kWh[/tex] = $[tex]10.676[/tex]
Hence, the annual cost is $[tex]10.676[/tex].
A) 100 watt = 0.1 kW
Annual cost can be calculated as:
Annual cost=0.1 kW ×6.50 h×365×0.13
=30.8 $
So, now the annual cost will be 30.8 $
B) 25 watt = 0.025 kW
Annual cost can be calculated as:
Annual cost=0.025 kW ×6.50 h×365×0.13
=7.71 $
So, now the annual cost will be 7.71 $
