Respuesta :
A point P on the line segment GK may be parametrically represented as
[tex]P = (1-t)G + tK[/tex]
t is a real parameter which controls where on the segment P is. t=0 means P=G, t=1 means P=K. We're interested in the t that gives a 3:2 ratio for PG:PK. That's closer to K so t>1/2. t=3/(3+2) = 3/5.
[tex]P=(1-3/5)(1,2) + (3/5)(8,12) = (2/5,4/5)+(24/5,36/5)=(26/5,40/5)=(26/5,8)[/tex]
Answer: (26/5, 8)
Answer: (5.2, 8)
Step-by-step explanation:
Given : G(1,2) and K (8,12).
To find : The coordinates of P that partitions gk in the ratio of 3:2
Section formula :
The line segment having endpoints (a,b) and (c,d) is divided in ration m:n by point M , then the coordinates of the M will be :-
[tex]x=\dfrac{mc+na}{m+n}\ ;\ y=\dfrac{md+nb}{m+n}[/tex]
Similarly,
[tex]x=\dfrac{3(8)+2(1)}{3+2}\ ;\ y=\dfrac{3(12)+2(2)}{3+2}[/tex]
Now simplify , we get
x=5.2 and y=8
Hence, the coordinates of P that partitions GK in the ratio of 3:2 = (5.2, 8)