In the x-y plane, the point (3,1) lies on the graph of the function g. If g(x) = a - 2 x^2, where a is a constant, what is the value of a ?

Respuesta :

The points on the graph of a function are all of the form

[tex] (x,g(x)) [/tex]

In fact, the graph is composed by all points [tex] (x,y) [/tex] such that y is the image of x, as written above.

So, if [tex] (3,1) [/tex] lies on graph, it means that [tex] g(3)=1 [/tex].

Since we know the expression for [tex] g(x) [/tex], we can plug the values:

[tex] g(3) = a-2(3)^2 = a-18 = 1 [/tex]

We can solve for [tex] a [/tex] by adding 18 to both sides to get [tex] a=19 [/tex].

So, the expression for the function is [tex] g(x) = 19-2x^2 [/tex]