Respuesta :

the inverse of a two-by-two matrix

A=[tex] \left[\begin{array}{ccc}a&b\\c&d\end{array}\right] [/tex]

whose inverse is

[tex]A^{-1}=\frac{\left[\begin{array}{ccc}d&-b\\-c&a\end{array}\right]}{ad-bc}[/tex]

Substituting values, we get

[tex]A^{-1}=\frac{\left[\begin{array}{ccc}7&9\\-8&-5\end{array}\right]}{37}[/tex]

which is not the same as matrix B. Therefore B is not the inverse of A.

We can prove similarly that A is not the inverse of B.