Amount of silver nitrate taken = 269.μmol [tex] AgNO_{3} [/tex]
Volume of the solution = 300. mL
Concentration of a solution is generally expressed in terms of molarity. Molarity is defined as the moles of a substance present per liter of the solution.
[tex] Molarity = \frac{Moles of solute}{Volume of solution(L)} [/tex]
We want the concentration in millimoles/L.
Converting μmol to millimol solute:
[tex] 269. [/tex]μ[tex] mol * \frac{1 millimol}{1000 micromol} [/tex] = 0.269 millimol
Volume from mL to L: [tex] 300. mL * \frac{1 L}{1000 mL} = 0.300 L [/tex]
Therefore concentration of the chemist's solution = [tex] \frac{0.269 millimol}{0.300 L} = 0.897 \frac{millimol}{L} [/tex]
