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Suppose there were x unripe oranges.
there were 18 more ripe oranges than unripe oranges
Means number of ripe oranges = x + 18
There were 24 rotten oranges too.
So, the sum of all oranges will be = [tex] x + (x + 18) + 24 [/tex]
So, the sum of all oranges will be = [tex] 2 x + 42 [/tex]
As per given in question, sum of total oranges are 84.
Hence making them equal
[tex] 2 x + 42 = 84 [/tex]
Subtracting 42 from both sides
[tex] 2x + 42 - 42 = 84 - 42 [/tex]
[tex] 2 x = 42 [/tex]
Dividing 2 in both sides
[tex] \frac{2x}{2} = \frac{42}{2} [/tex]
x = 21
Means number of unripe oranges = 21
Means number of ripe oranges = 21 + 18 = 39
Number of rotten oranges = 24
the ratio of the number of ripe oranges to the number of rotten oranges to the number of unripe oranges = [tex] 39 : 24 : 21 [/tex] : Answer
Hope it will answer :)
Answer:
39:24:21
Step-by-step explanation:
rotten = 24
ripe = x+18
unripe = x
x+x+18+24=84 oranges
-24 -24
2x+18=60 oranges
-18 -18
2x=42 oranges
÷2 ÷2
x=21
rotten = 24
ripe = x +18 = 39
unripe = x = 21
The ratio would be
39:24:21
