The general equation of a line in slope intercept form is [tex] y=mx+c [/tex] , where m is the slope.
The slope of the line given = 3/4
So here m = 3/4. We can write the equation as
[tex] y=(3/4) x+c [/tex]
[tex] y = 3x/4 + c [/tex]
Now given, the equation passes through the origin.
That means the equation passes through the point (0,0).
We will place x =0 and y =0, to get c here.
[tex] y = (3/4) x +c [/tex]
[tex] 0 = (3/4) (0) +c [/tex]
[tex] 0 = 0 + c [/tex]
[tex] c =0 [/tex]
We have got the value of c, so the equation of the line is
[tex] y = 3x/4 + 0 [/tex]
[tex] y = 3x/4 [/tex]
So the required equation of the line is [tex] y = 3x/4. [/tex]
