Respuesta :
[tex] \Omega=\{rr,bb,gg,yy,rb,rg,ry,bg,by,gy,yg,yb,gb,yr,gr,br\}\\
|\Omega|=16\\
A=\{rr,bb,gg,yy\}\\
|A|=4\\\\
P(A)=\dfrac{4}{16}=\dfrac{1}{4}=25\% [/tex]
Answer:
0.25
Step-by-step explanation:
Let
r = red
b = blue
g = green
y = yellow
- If the first chip is r, the second can be r, b, g or y. The 4 possibilities are rr, rb, rg, ry.
- If the first chip is b, the second can be r, b, g or y. The 4 possibilities are br, bb, bg, by.
- If the first chip is g, the second can be r, b, g or y. The 4 possibilities are gr, gb, gg, gy.
- If the first chip is y, the second can be r, b, g or y. The 4 possibilities are yr, yb, yg, yy.
From the 4 + 4 + 4 + 4 = 16 possible outcomes, there are 4 in which the chips are of the same color (rr, bb, gg, yy). The probability that the two chips selected are the same color is
4/16 = 0.25 = 25%