Assume a binomial distribution. Then the mean of the distribution is [tex]np[/tex], where [tex]n[/tex] is the number of people taken in a sample and [tex]p[/tex] is the probability of the mutation occurring in any given person, and the standard deviation is [tex]\sqrt{np(1-p)}[/tex]. Then in this case, the standard deviation is [tex]\sqrt{600(0.06)(0.94)}\approx5.82[/tex].
