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A point charge of 6.8 C moves at 6.5 × 104 m/s at an angle of 15° to a magnetic field that has a field strength of 1.4 T. What is the magnitude of the magnetic force acting on the charge? 1.6 × 10–1 N 6.0 × 10–1 N 1.6 × 105 N 6.0 × 105 N
(please show your work in solving this)

Respuesta :

Force on a moving charge is given by

[tex]F = q(v x B)[/tex]

Given that

q = 6.8 C

[tex]v = 6.5 * 10^4 m/s[/tex]

B = 1.4 T

angle = 15 degree

[tex]F = qvB sin\theta[/tex]

[tex]F = 6.8*6.5 * 10^4 * 1.4 * sin15[/tex]

[tex]F = 1.6 * 10^5 N[/tex]

Answer:

1.6 × 10–1 N

Explanation:

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