we are given
[tex] s(t)=170-80e^{-0.7t} [/tex]
Firstly , we can find derivative
[tex] s'(t)=0-80*-0.70e^{-0.7t} [/tex]
now, we can simplify it
[tex] s'(t)=56e^{-0.7t} [/tex]
now, we can plug t=2
[tex] s'(2)=56e^{-0.7*2} [/tex]
[tex] s'(2)=13.80943 [/tex]..............Answer