We have the cards numbered as 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, and 12.
Sample number is, n(S)=11.
We pick a card and want to get even number like 2, 4, 6, 8, 10, and 12.
Probability of picking an even number would be :-
P(even numbers) = [tex] \frac{6}{11} [/tex]
Now we replace the card and want to get a 7 in second attempt.
Probability of picking a 7 would be :-
P(number 7) = [tex] \frac{1}{11} [/tex]
Now Probability of this event = P(even numbers) × P(number 7)
Probability = [tex] (\frac{6}{11} )(\frac{1}{11} ) = \frac{6}{121} [/tex]
So final answer is [tex] \frac{6}{121} [/tex].
