Each of 6 ladies randomly chooses a woolen overcoat from 15 different styles. what is the probability that at least 2 ladies choose the same type of overcoat?

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[tex] {\text{Total number of woolen overcoat = 15}} \hfill \\
{\text{Number of ladies in a group = 6}} \hfill \\
{\text{Each lady has 15 choices, which can happen in = 1}}{{\text{5}}^6}{\text{ ways}} \hfill \\
{\text{If no two ladies have the same choices, then each lady can select any overcoat}}. \hfill \\
{\text{Six ladies can select the woolen overcoat in = 15}} \times {\text{14}} \times {\text{13}} \times {\text{12}} \times {\text{11}} \times {\text{10 ways}} \hfill \\ [/tex][tex] \therefore \,{\text{The probability that no two ladies select the same overcoat = }}P\left( E \right){\text{ = }}\frac{{{\text{15}} \times {\text{14}} \times {\text{13}} \times {\text{12}} \times {\text{11}} \times {\text{10 }}}}{{{\text{1}}{{\text{5}}^6}}}\; \hfill \\
\therefore \,{\text{The probability that atleast two ladies select the same overcoat }} \hfill \\
\,\,\,{\text{ = }}\,{\text{1}} - P\left( E \right) \hfill \\ [/tex][tex] \,\,\,{\text{ = }}\,{\text{1}} - \frac{{{\text{15}} \times {\text{14}} \times {\text{13}} \times {\text{12}} \times {\text{11}} \times {\text{10 }}}}{{{\text{15}} \times {\text{15}} \times {{15}^4}}}\hfill \\
\,\,\,{\text{ = }}\,{\text{1}} - \frac{{{\text{14}} \times {\text{13}} \times {\text{4}} \times {\text{11}} \times {\text{2 }}}}{{{{15}^4}}} \hfill \\
\,\,\,{\text{ = }}\,{\text{1}} - \frac{{{\text{16016 }}}}{{{\text{50625}}}} \hfill \\ [/tex][tex] \,\,\,{\text{ = }}\,{\text{1}} - {\text{0}}{\text{.316}} \hfill \\
\,\,\,{\text{ = }}\,0.684 \hfill \\ [/tex]

The probability that at least 2 ladies choose the same type of overcoat will be 0.32.

What is probability?

Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.

Each of the 6 ladies randomly chooses a woolen overcoat from 15 different styles.

Then the probability that at least 2 ladies choose the same type of overcoat will be

The total number of the event will be

Total events = 15⁶

The favorable event will be

Favorable event = 15 x 14 x 13 x 12 x 11 x 10

Then the probability will be

P = (15 x 14 x 13 x 12 x 11 x 10) / 15⁶

P = 0.31636

P = 0.32

More about the probability link is given below.

https://brainly.com/question/795909

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