The flow rate of a liquid through a 2.0 cm radius pipe is 0.008 m3 /s. the average fluid velocity in the pipe is:

Respuesta :

The average fluid velocity in the pipe can be obtained by dividing the flow rate of the liquid by the cross-sectional area of the pipe.

Av velocity = Flow rate/Cross-sectional area

Given, flow rate of the liquid = 0.008 m³/s

Cross-sectional area = [tex] \pi Radius^{2} [/tex] , radius of the pipe is 0.02 m.

Substituting the values we get,

Av velocity= [tex] \frac{0.008}{\frac{22}{7}*(0.02)^{2}} [/tex]

= 6.36 m/s

Average velocity of the fluid is 6.36 m/s.

Velocity of fluid in the pipe=6.37 m/s

Explanation:

radius of pipe= 2 cm= 0.02 m

The flow rate is given by Q = a v

Q= flow rate = 0.008 m³/s

a= area= πr²

a=π(0.02)²= 1.256 x 10⁻³ m²

so 0.008 = 1.256 x 10⁻³ (v)

v=6.37 m/s