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A diffraction grating gives a second-order maximum at as angle of 31° for violet light (λ = 4.0 × 102 nm). If the diffraction grating is 1.0 cm in width, how many lines are on this diffraction grating? [___/3]

Respuesta :

for second order maximum we can say

[tex]a sin\theta = \frac{5\lambda}{2}[/tex]

here we will have

[tex] a= \frac{0.01}{N}[/tex]

now we will have

[tex]\frac{0.01}{N} sin31 = \frac{5*400*10^{-9}}{2}[/tex]

[tex]N = \frac{0.01 * sin31}{5*200*10^{-9}}[/tex]

[tex]N = 5150[/tex]

so the number of lines are 5150.

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