contestada

2. How many more possible arrangements can be made using the letters of the word PERMUTATIONS than using the letters of the word COMBINATIONS? Justify your answer.

Respuesta :

konrad509

PERMUTATIONS - [tex] \dfrac{12!}{2!} [/tex]

COMBINATIONS - [tex] \dfrac{12!}{2!2!} [/tex]

[tex] \dfrac{\dfrac{12!}{2!}}{\dfrac{12!}{2!2!}}=\dfrac{12!}{2!}\cdot\dfrac{2!2!}{12!}=2!=2 [/tex]