Consider the following balanced reaction between hydrogen and nitrogen to form ammonia:
3H2(g) + N2(g)→2NH3(g)
How many moles of NH3 can be produced from 19.0 mol of H2 and excess N2?
Three moles of H2 produce 2 moles of NH3. Since the reactinng ratios are constant, then the ratio of hydrogen consumed:ammonia is 3:2 Mathematically, 3 Mol H2=2mol NH3 19 Molly H2=? Cross-multiplying gives; (19*2)/3=12.67 moles
